contestada

Using the discriminant, determine the number of real solutions. -4x^2+20x-25=0

A) no real solutions
B) one real solution
C) two real solutions

Respuesta :

mreijepatmat
-4x² + 20x - 25 = 0
The discriminant Δ = b² - 4.a.c, where a= -4; b= 20 & c = - 25
Then Δ = (20)² - 4(-4)(-25)
Δ = 0 , since the discriminant = 0, we have one real solution (answer B)

For more info about Δ, If :
Δ > 0, then there are 2 real solutions, x' and x"

Δ = 0, then there are 2 equal real solutions, x' = x"

Δ < 0, then there are no solutions, or 2 imaginary values of x' and x"
MrRoyal

Discriminant are used to determine the number of solutions of a quadratic equation

The number of solutions is (b) one real solution

The equation is given as:

[tex]\mathbf{-4x^2 + 20x - 25 = 0}[/tex]

A quadratic equation is represented as:

[tex]\mathbf{ax^2 + bx + c = 0}[/tex]

Where the discriminant is:

[tex]\mathbf{d = b^2 - 4ac}[/tex]

So, we have:

[tex]\mathbf{d = (20)^2 - 4 \times -4 \times -25}[/tex]

[tex]\mathbf{d = 400 - 400}[/tex]

[tex]\mathbf{d = 0}[/tex]

If the discriminant is 0, then the equation has 1 real root.

Hence, the number of solutions is (b) one real solution

Read more about discriminant at:

https://brainly.com/question/9970081

Otras preguntas