A.
so we are given 2 points, (2,14) and (5,29)
we will use slope intercept form then convert to standard form
y=mx+b
m=slope
b=y intercept
first find slope
slope between the points (x1,y1) and (x2,y2) is
(y2-y1)/(x2-x1)
so
slope
(2,14) and (5,29)
slope=(29-14)/(5-3)=15/3=5
y=5x+b
find b
use a point
(2,14)
x=2 and y=14
14=5(2)+b
14=10+b
4=b
so
y=5x+4 is da equation
standard form, solve for ax+by=c
5x-y=-4
B.
that is solve for y and replace y with f(x)
y=5x+4
f(x)=5x+4
C.
one way is to subsitute points
when x=0, y=4
when x=1, y=9
graph theh points (0,4) and (1,9)
maybe graph the intercepts
x intercept is (-5/4,0)
y intercept is (0,4)