Answer:
[tex]4x+8\text{and}x^2-4[/tex]
Step-by-step explanation:
Extraneous is the point where the solution of a function exists and it gives the value of denominator zero
In case of [tex]f(x)=4x+8=0[/tex]
can be the denominator in sally's function.
In case of [tex]f(x)=2(-2)+12=8[/tex] not the possible denominator because we are not getting zero at this point.
In case of [tex]f(x)=(-2)^2-4=0[/tex] is the possible denominator
in case of [tex]f(x)=x^2-16=(-2)^2-16=-12[/tex] is the not the possible denominator.
