What is the gauge pressure of the blood as it moves past the constriction? the density of blood is 1050 kg/m3. express your answer to two significant figures and include the appropriate units?

Respuesta :

2/Blood flows at an average speed of 0.40 m/s in a horizontal artery of radius 1.0 cm. The average pressure is 1.4 × 104N/m2 above atmospheric pressure (the gauge pressure).

The gauge pressure of the blood is the difference between the absolute

blood pressure and the atmospheric pressure.

  • The gauge pressure of the blood as it moves past the constriction is approximately 3·7 × 10³ N/m

Reasons:

The given parameters are;

Radius of the blood vessel, r₁ = 1.0 cm = 0.01 m

Average speed of the blood, v₁ = 0.40 m/s

Average pressure of blood, P = 1.4 × 10⁴ N/m²

The radius of the constriction, r₂ = 0.30 cm = 0.003 m

Density of blood, ρ = 1,050 kg/m³

The velocity of the blood past the constriction is given as follows;

The continuity equation is; v₁ × A₁ = v₂ × A₂

A₁ = π × r₁²

A₁ = π × (0.01 m)² = 0.0001·π m²

A₂ = π × (0.003 m)² = 0.000009·π m²

[tex]\displaystyle v_2 = \mathbf{\frac{v_1 \times A_1}{A_2}}[/tex]

[tex]\displaystyle v_2 = \frac{0.4 \ m/s \times 0.0001 \cdot \pi \ m^2}{0.000009 \cdot \pi \ m^2} = 4. \overline 4 \ m/s[/tex]

The speed of the blood after the constriction, v₂ = [tex]\mathbf{4. \overline 4}[/tex] m/s

Dynamic pressure due to speed of fluid is given by the formula;

[tex]\displaystyle P = \mathbf{\frac{\rho \cdot v^2}{2}}[/tex]

Therefore;

[tex]\displaystyle \frac{\rho \cdot v_2^2}{2} = \frac{1,050 \ kg/m^3 \times (4.\overline 4 \ m/s)^2}{2} = 10370. \overline{370} \ Pa[/tex]

[tex]\displaystyle \frac{\rho \cdot v_1^2}{2} = \frac{1,050 \ kg/m^3 \times (0.4\ m/s)^2}{2} = 84 \ Pa[/tex]

According to Bernoulli's equation, for blood vessel section at the same level, we have;

  • [tex]\displaystyle P_1 + \frac{\rho \cdot v_1^2}{2} = \mathbf{P_2 + \frac{\rho \cdot v_2^2}{2}}[/tex]

Which gives;

[tex]\displaystyle P_2 = P_1 + \frac{\rho \cdot v_1^2}{2} - \frac{\rho \cdot v_2^2}{2}[/tex]

[tex]\displaystyle P_2 = 1.4 \times 10^4 + 84 -10370. \overline{370} \approx 3,713.6296[/tex]

P₂ ≈ 3,713.6296 N/m²

  • The gauge pressure of the blood as it moves past the constriction, given to two significant figures P₂ ≈  3,700 N/m² = 3.7 × 10³ N/m²

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