A 2.5 g sample of french fries is placed in a calorimeter with 500.0 g of water at an initial temperature of 21 °C. After combustion of the french fries, the water has a temperature of 48 °C. What is the caloric value (kcal/g) of the french fries?

Respuesta :

q=m°CΔT
=(500g) x (1 cal/g.
°C) x (48°C-21°C) = 13500 cal
13500 cal / 1000 = 13.5 kcal

"What is the caloric value (kcal/g) of the french fries?"
13.5 kcal/ 2.5 g = 5.4 kcal/g

5.4 kcal/g is the caloric value of the french fries.

Explanation:

  • The amount of heat generated by the combustion of a unit quantity of the substance is termed as caloric value.

Given :

The mass of a sample of the french fries = 2.5 g

The mass of water in calorimeter = 500.0 g

The initial temperature of the water = 21 °C

The final temperature of the water =48 °C

To find:

The caloric value of the french fries

Solution:

The mass of water in calorimeter = m= 500.0 g

The initial temperature of the water =[tex]T_i=21^oC[/tex]

The final temperature of the water =[tex]T_f=48^oC[/tex]

The specific heat of the water = c =[tex]4.186 J/g^oC[/tex]

The amount of heat absorbed by the water due to combustion of french fries= Q

[tex]Q=m\times c\times (T_f-T_i)\\\\Q=500.0 g\times 4.186 J/g^oC\times (48^oC-21^o)\\[/tex]

[tex]Q=56,511 J\\1 calorie= 4.186 Joules\\Q=56,511 J=56,511\times \frac{1}{4.186 }cal=13,500 cal[/tex]

The amount heat released on combustion of 2.5 grams of french fries = Q'

Q ' = -Q  (Law of conservation of energy)

Q'= -13,500 cal

(Negative sign means that heat energy was released)

The mass of a sample of the french fries = M = 2.5 g

The caloric value of the french fries:[tex]=\frac{Q'}{M} =\frac{-13,500 cal}{2.5 g}=5,400 cal/g\\1 cal = 0.001 kcal\\= 5,400 cal/g=5,400\times 0.001 kcal/g=5.4 kcal/g[/tex]

5.4 kcal/g is the caloric value of the french fries.

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