Respuesta :
T=20 min
m₀=200 g
t=60 min
the mass of element through time t is:
m=m₀*2^(-t/T)
m=200*2^(-60/20)=25 g
25 grams of element will be left after 60 minutes
m₀=200 g
t=60 min
the mass of element through time t is:
m=m₀*2^(-t/T)
m=200*2^(-60/20)=25 g
25 grams of element will be left after 60 minutes
Answer: 25 grams
Explanation:
Radioactive decay follows first order kinetics.
Half-life of element = 20 minutes
[tex]\lambda =\frac{0.693}{t_{\frac{1}{2}}}=\frac{0.693}{20}=0.035min^{-1}[/tex]
[tex]N=N_o\times e^{-\lambda t}[/tex]
N = amount left after time t = ?
[tex]N_0[/tex] = initial amount = 200 g
[tex]\lambda[/tex] = rate constant
t= time = 60 min
[tex]N=200\times e^{- 0.035 min^{-1}\times 60 min}[/tex]
[tex]N=25g[/tex]
Thus amount left after 60 minutes will be 25 grams.
