Cost of missing tickets is equals to
Cost of 2nd ticket = $5.00
Cost of 4th ticket = $10.00
Cost of 8th ticket = $20.00
Cost of 9th ticket = $22.50
Total cost of nine tickets is equals to 112.50.
What is cost?
" Cost is defined as the amount to pay on any purchase,"
According to the question,
Total number of tickets =9
Total Cost 1 $2.50
Total Cost 3 $7.50
Total Cost 5 $12.50
Total Cost 6 $15.00
Total Cost 7 $17.50
Pattern follow by cost on each ticket price increased by = $2.50
Cost of 2nd ticket = cost of 1st ticket + $2.50
= $2.50 + $2.50
= $5.00
Cost of 4th ticket = Cost of 3rd ticket + $2.50
= $7.50 + $2.50
= $ 10.00
Cost of 8th ticket = Cost of 7th ticket + $2.50
= $17.50 + $2.50
= $ 20.00
Cost of 9th ticket = Cost of 8th ticket + $2.50
= $20.00 + $2.50
= $22.50
Hence, Cost of missing tickets is equals to
Cost of 2nd ticket = $5.00
Cost of 4th ticket = $10.00
Cost of 8th ticket = $20.00
Cost of 9th ticket = $22.50
Total cost of nine tickets is equals to 112.50.
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