Respuesta :
Setup Fee= $5,500Per CD Charge= $1.00Desired Cost Per CD= $3.50
x= number of CDs
Desired Cost Per CD= Cost per CD + Setup Fee
($3.50 * x)= ($1.00 * x) + $5,500multiply inside parentheses
$3.50x= $1.00x + $5,500subtract $1.00x from both sides
$2.50x= $5,500divide both sides by $2.50
x= 2,200 CDs
ANSWER: x= 2,200 CDs
Hope this helps! :)
x= number of CDs
Desired Cost Per CD= Cost per CD + Setup Fee
($3.50 * x)= ($1.00 * x) + $5,500multiply inside parentheses
$3.50x= $1.00x + $5,500subtract $1.00x from both sides
$2.50x= $5,500divide both sides by $2.50
x= 2,200 CDs
ANSWER: x= 2,200 CDs
Hope this helps! :)
Hi there!
Let th' number of CD's be = X
• Setup fee = $ 5,500
• Per CD's charge = $ 1.00
• Desired cost per CD = $ 3.50
Acc'rding to the question :-
Desired cost per CD = Setup fee + Cost per CD
⇒ (3.50 × X) = $ 5, 500 + ($ 1.00 × X)
⇒3.50 X = $ 5, 500 + 1.00 X
Combine like terms :-
⇒ 3.50 X - $ 1.00 X = $ 5, 500
⇒ 2.50 X = $ 5, 500
⇒X = [tex]\dfrac {5, 500}{2.50}[/tex] = 2, 200 CD's
Hence,
The required answer is = X = 2, 200 CD's
~ Hope it helps!
Let th' number of CD's be = X
• Setup fee = $ 5,500
• Per CD's charge = $ 1.00
• Desired cost per CD = $ 3.50
Acc'rding to the question :-
Desired cost per CD = Setup fee + Cost per CD
⇒ (3.50 × X) = $ 5, 500 + ($ 1.00 × X)
⇒3.50 X = $ 5, 500 + 1.00 X
Combine like terms :-
⇒ 3.50 X - $ 1.00 X = $ 5, 500
⇒ 2.50 X = $ 5, 500
⇒X = [tex]\dfrac {5, 500}{2.50}[/tex] = 2, 200 CD's
Hence,
The required answer is = X = 2, 200 CD's
~ Hope it helps!