Respuesta :
Acceleration is 3 f/ts
you subtract then divide
(45-60)/5
you subtract then divide
(45-60)/5
Answer:
[tex]3\ ft/s^2.[/tex]
Explanation:
It is given that initial speed of car, [tex]v_i=45\ ft/s.[/tex]
Also, final speed of car, [tex]v_f=60\ ft/s.[/tex]
Time taken by the car during this process, [tex]t=5\ s.[/tex]
We need to find the acceleration of car, a.
Now, by newton's equation of motion.
We know, [tex]v_f-v_i=a\times t[/tex]
Putting all required values in above equation.
[tex]60-45=5\times a.\\a=3\ ft/s^2.[/tex]
Therefore, the acceleration by the car during this process is [tex]3\ ft/s^2.[/tex]
Hence, it is the required solution.