Respuesta :
Answer:
The y-value of P' is -10.
Step-by-step explanation:
We have been given the vertices of triangle PQR as: P(–2, 6), Q(–8, 4), and R(1, –2). We are asked to find the y-coordinate of point P' after a translation of (x, y) → (x – 2, y – 16).
We can see that our given translation rule states that we need to translate x-coordinates of triangle PQR to 2 units to right and y-coordinates will be shifted downwards by 16 units.
[tex]P(-2,6)\rightarrow P'(-2-2,6-16)[/tex]
[tex]P(-2,6)\rightarrow P'(-4,-10)[/tex]
We can see that y-coordinate of point P' is -10, therefore, the y-value of P' is -10.
You can use the fact that when the figure is origin shifted, then all its coordinates are shifted.
The y-value of P' is -10
How to draw a shifted figure if the shifts are provided?
Suppose the graph is drawn on the coordinate plane.
Let the shifting be (x,y) → (x+a, y+b)
Then, add 'a' to all x coordinates of the graph's points. Add 'b' to all y coordinates of the graph's points.
The resultant set of new points will be plotted.
Why is (x,y) → (x+a, y+b) shifting called origin shift?
it is called origin shift since we think of it as the origin was picked and placed at the point (a,b)(in this case) along with those two axes (x and y axes) and now everything will be measured from this new axes' frame.
Using the above facts to find the y-value of P:
Since the coordinate of P are (-2,6) and the the origin shift is
(x, y) → (x – 2, y – 16)
Doing the shift, we get:
(-2, 6) → (-2– 2, 6 – 16) = (-4, -10)
Thus,
The y-value of P' is -10
Learn more about origin shift of graph in coordinate axis here:
https://brainly.com/question/11901218
