If a sample contains 21.2 g N, how many moles of N does it contain? 0.66 mol 1.51 mol 14.01 mol 297.01 mol

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dec77cat dec77cat · Answer 1 · 2017-06-02T16:51:17+02:00

m(N)=21.2 g
M(N)=14.007 g/mol

n(N)=m(N)/M(N)

n(N)=21.2g/(14.007g/mol)=1.51 mol

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dexteright02 dexteright02 · Answer 2 · 2018-12-26T00:18:57+01:00

Hello!

If a sample contains 21.2 g N, how many moles of N does it contain?

0.66 mol

1.51 mol

14.01 mol

297.01 mol

We have the following data:

m (mass) = 21.2 g

MM (Molar mass of Nitrogen) = 14 g / mol

n (number of moles) = ?

Formula:

[tex]n = \dfrac{m}{MM}[/tex]

Solving:

[tex]n = \dfrac{m}{MM}[/tex]

[tex]n = \dfrac{21.2\:\diagup\!\!\!\!\!g}{14\:\diagup\!\!\!\!\!g/mol}[/tex]

[tex]\boxed{\boxed{n\approx 1.51\:mol}}\end{array}}\qquad\checkmark[/tex]

Answer:

1.51 mol

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I Hope this helps, greetings ... Dexteright02! =)