Respuesta :
m(NH₃)=345 g
M(NH₃)=A(N)+3A(H)
M(NH₃)=14.0+3·1.0=17.0g/mol
n(NH₃)=m(NH₃)/M(NH₃)
n(NH₃)=345g/17.0g/mol=20.3 mol
M(NH₃)=A(N)+3A(H)
M(NH₃)=14.0+3·1.0=17.0g/mol
n(NH₃)=m(NH₃)/M(NH₃)
n(NH₃)=345g/17.0g/mol=20.3 mol