A software store has put some of its inventory on sale. Games are marked down by 15%, and security programs are marked down by 18%. If you pay $35.70 each for two games and $22.96 for a security program, how much have you saved?


The answer is A $17.64

Respuesta :

1 game 15%

1 security program 18%

15% of 35.70 = $5.4 with 2 games you saved $10.8 so far
18% of 22.96 = $4.1 + 10.8 = $14.9

Answer: Amount he saved is $17.64.

Step-by-step explanation:

Let the actual price of each game be 'x'.

Let the actual price of security program be 'y'.

Since we have given that

Games are marked down by 15%.

Security programs are marked down by 18%.

Amount paid by him on each game = $35.70

So, Amount paid by him on two games = 35.70 × 2 = $71.4

So, Price of games becomes,

[tex]\frac{85}{100}\times x=\$71.4\\\\x=71.4\times \frac{100}{85}\\\\x=\$84[/tex]

Similarly,

Amount of security program paid by him = $22.96

So, Cost of security program is given by

[tex]\frac{100-18}{100}\times y=\$22.96\\\\\frac{82}{100}\times y=\$22.96\\\\y=\frac{100}{82}\times 22.96\\\\y=28[/tex]

Hence, Original price of games and security program is $84+$28=$112.

total amount he paid is given by

71.40+22.96=$94.36

So, Amount he saved is given by

Original price - Amount paid

$112-$94.36

=$17.64