Respuesta :
11) q = (m)(Cp)(final temperature- initial temperature) 520 J = (200 g)(cp)(20)---->since the heat capacity is in JOULES convert KJ to Joules so .52 kj = 520 J .13 = Cp, which is gold, so D is your answer.
12) q = (20)(334) q = 6,680 J q = 6.68 KJ, which is D, so D is your answer.
13) q = (m)(cp)(final temperature-initial temperature) q = (150)(.92)(15) q = 2070 J q = 2.07 KJ, which is B, so B is your answer.
18) q = (3.16)(.50) q = 1.58 KJ, which is C, so C is your answer.
19) q = (.13 mol)(40.67 kj/mol) q = 565 KJ, which is D, so D is your answer. I hope this helps!
12) q = (20)(334) q = 6,680 J q = 6.68 KJ, which is D, so D is your answer.
13) q = (m)(cp)(final temperature-initial temperature) q = (150)(.92)(15) q = 2070 J q = 2.07 KJ, which is B, so B is your answer.
18) q = (3.16)(.50) q = 1.58 KJ, which is C, so C is your answer.
19) q = (.13 mol)(40.67 kj/mol) q = 565 KJ, which is D, so D is your answer. I hope this helps!
Answer: ammonia
Explanation:
[tex]Q= m\times c\times \Delta T[/tex]
Q= heat gained = 18.8 kJ
m= mass of the substance = 200 g
c = heat capacity of unknown substance= ? J/g ° C
[tex]\Delta T={\text{Change in temperature}}=(45-25)^0C=20^oC[/tex]
[tex]18800J=200g\times cJ/g^oC\times20^oC[/tex]
[tex]c=4.7J/g^0C[/tex]
Thus the unknown substance is ammonia which has a heat capacity of [tex]4.7J/g^0C[/tex]