a gas sample is heated from -20 to 57 C and the volume is increased from 2.00 L to 4.50 L. If the initial pressure is 0.109 atm, what is the final pressure?

According to the combined gas laws we can write P1*V1/T1 =P2*V2/T2.we have initial pressure which is P1=0.109atm.Initial vol V1=2litres and initial temperature is -20 degree C which is 273-20K i.e.,T1=253K.and final volume isV2= 4.50 litres and final temp is 57 degree C which is 273+57K i.e.,T2=330K so according to the question we need to find out P2.which is 0.109*2*330÷4.50*253=0.0632atm which is the final pressure.

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kumaripoojavt kumaripoojavt · Answer 2 · 2022-07-13T12:56:57+02:00

0.0632atm is the final pressure if a gas sample is heated from -20 to 57 C and the volume is increased from 2.00 L to 4.50 L.

What is an ideal gas equation?

The ideal gas law (PV = nRT) relates the macroscopic properties of ideal gases. An ideal gas is a gas in which the particles (a) do not attract or repel one another and (b) take up no space (have no volume).

According to the combined gas laws, we can write:

[tex]P_1V_1 T_2 =P_2V_2T_1[/tex]

[tex]P_1[/tex] =0.109atm.

[tex]V_1[/tex] =2litres and

Initial temperature is -20 degrees C which is 273-20K

[tex]T_1[/tex] =253K

[tex]V_2[/tex] = 4.50 litres

The final temp is 57 degree C which is 273+57K i.e.,

[tex]T_2[/tex] =330K

So, according to the question we need to find out [tex]P_2.[/tex]

[tex]P_1V_1 T_2 =P_2V_2T_1[/tex]

[tex]P_2[/tex]=0.109 x 2 x 330 ÷ 4.50 x 253

[tex]P_2[/tex]=0.0632atm is the final pressure.

Hence, 0.0632atm is the final pressure.

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https://brainly.com/question/27691721

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