What volume of o2 at 874 mmhg and 33 ∘c is required to synthesize 18.0 mol of no?

1) Write the balanced chemical equation

4NH3 + 5O2 ----> 4NO + 6H2O

2) Write the molar ratios

4 mol NH3 : 5 mol O2 : 4 mol NO : 6 mol H2O

3) Write the proportions with the desired quantity of NO and the unknown quantity of O2

5 mol O2 / 4 mol NO = x / 18.0 mol NO

Solve for x: x = 18.0 mol NO * 5 mol O2 / 4 mol NO = 22.5 mol O2

4) Use the ideal gas equation to convert moles to volume

pV = nRT => V = nRT / p

n = 22.5 mol

R = 0.082 atm*liter / K * mol

T = 33 + 273.15 = 306.15 K

p = 874/760 atm = 1.15 atm

V = 22.5 mol * 0.082 atm*liter/K*mol * 306.15 K / 1.15 atm = 491.17 liter

Answer: 491 liters of O2

ardni313 ardni313 · Answer 2 · 2019-07-19T16:13:30+02:00

490.93 liters is required to synthesize 18.0 mol of NO

Further explanation

Stokiometry in Chemistry learn about chemicals mainly emphasizes quantitative, such as the calculation of volume, mass, number, which is related to numbers, molecules, elements, etc.

A reaction coefficient is a number in the chemical formula of a substance involved in the reaction equation. The reaction coefficient is useful for equalizing reagents and products.

In the reaction there are also manifestations of reagent substances namely gas (g), liquid (liquid / l), solid (solid / s) and solution (aqueous / aq).

Reactions that occur:

4NH₃ (g) + 5O₂ (g) -> 4NO (g) + 6H₂O (g)

Comparison of coefficient = mole ratio

So that mole O₂ = 5/4 x mol NO

mole O₂ = 5/4 x 18

mole O₂ = 22.5

To find the volume, assuming the ideal gas, we use the formula:

[tex]\large{\boxed{\boxed{\bold{PV=nRT}}}[/tex]

P = 874 mmhg = 874/760 mmhg = 1.15 atm

R = 0.082 L atm / mole K

T = 33 + 273 = 306 K

V = nRT / P

V = 22.5 0.082.306 / 1.15

V = 490.93 liters

Learn more

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Keywords: ideal gas law, mole, NO, O₂