Respuesta :
If you were to take both halves of the carpet and place them on top of each other you can see that the two triangle sections would cover each over up and fill in to make a rectangle. So first, lets compute the size of the middle section, then we will compute the size of the end pieces.
The center section of the carpet is 30 ft x 31 ft = 930 sq ft
The ends of the carpet are 12 ft x 15.5 ft = 186 sq ft
Since there are two side to the carpet like this we multiply this by 2
186 * 2 = 372 sq ft
Adding these two values together gives
930 + 372 = 1302 sq ft
The center section of the carpet is 30 ft x 31 ft = 930 sq ft
The ends of the carpet are 12 ft x 15.5 ft = 186 sq ft
Since there are two side to the carpet like this we multiply this by 2
186 * 2 = 372 sq ft
Adding these two values together gives
930 + 372 = 1302 sq ft
Answer:
It will cost $ 3348 to carpet the lobby.
Step-by-step explanation:
Refer the attached figure
AB divides the figure into two congruent trapezium
Height of trapezium = 15.5 feet
Parallel sides = 30 feet and 42 feet
Area of one trapezium = [tex]\frac{1}{2} \times \text{Sum of parallel sides} \times Height[/tex]
Area of one trapezium = [tex]\frac{1}{2} \times (30+42) \times15.5[/tex]
= [tex]558 ft^2[/tex]
So, Area of both trapeziums = [tex]558 \times 2 = 1116 ft^2[/tex]
So, Total Area of the floor is 1116 sq.feet.
Cost of carpet of 1 sq.ft. = $3
Cost of carpet of 1116 sq.ft. = [tex]1116 \times 3 =3348[/tex]
Hence it will cost $ 3348 to carpet the lobby.