Respuesta :
probabltity=desired outcomes/total possible
the ones that sum to 4 are (depends on what die)
1 and 3
3 and 1
2 and 2
2 and 2
4 combinations
how many different possibitlies
6 sides so 6*6 for 2 dice
so 4/36 is porbablity or 1/9
1/9 of all of them so
about 1000/9 times or about 111.1111 times, (rounded to 111 times)
the ones that sum to 4 are (depends on what die)
1 and 3
3 and 1
2 and 2
2 and 2
4 combinations
how many different possibitlies
6 sides so 6*6 for 2 dice
so 4/36 is porbablity or 1/9
1/9 of all of them so
about 1000/9 times or about 111.1111 times, (rounded to 111 times)
Answer: about 83
Step-by-step explanation: the answer is 83 since
3/36 = 1/12 = 0.083 is the probability of rolling a 4
0.083*1000 = 83 is the number of times we expect to roll a 4 out of 1000 trials