Answer:
2 hours walking and 12 hours running
Step-by-step explanation:
The choice to this question are
- 2 hours walking; 12 hours running
- 4 hours walking; 3 hours running
- 9 hours walking; 12 hours running
- 12 hours walking; 10 hours running
The given inequalities are
[tex]3w+6r\geq 36[/tex]
[tex]3w+6r\leq 90[/tex]
Where [tex]w[/tex] is walk and [tex]r[/tex] is run.
First, we need to graph this system. The image attached shows both inequalities and the area of solution, where [tex]x=w[/tex] and [tex]y=r[/tex].
In other words, any point in side the intesection of shaded areas is part of the solution to this problem.
So, 2 hours walking and 12 hours running is inside the area of solution, because represents point (2,12).
