This problem is a simple application of Gay-Lussac's Law for gases.
Gay - Lussac's Law states that the pressure and temperature (in absolute scale) of a gas are proportional.
This is:
p / T = constant => p1 / T1 = p2 / T2.
Here you have p1 = 160 kPa; T1 = 35.0 + 273.15 = 308.15 K; p2 = 250 KPa; T2 = ?
Then, just solve T2 from the equation above.
T2 = p2 * T1 / p1 = 250 kPa * 308.15K / 160 kPa = 481.48 K.
T2 = 481.48 - 273.15 = 208.33 °C.
Answer: 208.33 °C.