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peed of Plane A = 415 mph. Speed of Plane B = 375 mph. Both planes leave from New York City at the same time. Plane A flies due North. Plane B flies due South. After 4 hours, how far is Plane A from Plane B (to the nearest mile)?

Respuesta :

Aliwohaish12
415×4+375×4
=3,160 miles apart

Answer:

Hence, distance between Plane A and Plane B is:

3160 m.

Step-by-step explanation:

It is given that:

Speed of Plane A = 415 mph.

Speed of Plane B = 375 mph.

Now  Both planes leave from New York City at the same time. Plane A flies due North and  Plane B flies due South.

This means that Plane A and Plane B travels in the opposite directions.

So the distance between them keep on increasing with respect to time.

We know that:

Distance=Speed×Time.

The distance covered by Plane A in 4 hours=415×4=1660 m.

The distance covered by Plane B in 4 hours=375×4=1500 m.

Hence, distance between plane A and Plane B in 4 hours=1660+1500

        =3160 m.

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