Respuesta :
Answer: Please see attachment.
Solution:
We need to match the column using column proof. Please see the attachment for matching column.
In ΔDOC and ΔBOA
DO=BO (Given)
∠DOC=∠BOA (Vertically Opposite angle)
OC=OA (Given)
∴ ΔDOC ≅ ΔBOA by SAS congruence property
∠1=∠2 and AB=DC By CPCTE
Thus, AB||DC (∠1 and ∠2 are alternate angles equal then lines parallel)
ABCD is a parallelogram. ( If two sides equal and parallel then a parallelogram.
Below is matched table.
DO = OB, AO = OC ⇒ Given
∠ DOC =∠ AOB ⇒ Vertical angles are equal
∆COD ≅ ∆AOB ⇒ SAS CPCTE
∠1 = ∠2, AB = DC ⇒ CPCTE
AB||DC ⇒ If alternate interior angles =, then lines parallel
ABCD is a parallelogram ⇒ If two sides = and ||, then a parallelogram
Please see attachment for figure and matching.
Answer:
Answer: Please see attachment.
Solution:
We need to match the column using column proof. Please see the attachment for matching column.
In ΔDOC and ΔBOA
DO=BO (Given)
∠DOC=∠BOA (Vertically Opposite angle)
OC=OA (Given)
∴ ΔDOC ≅ ΔBOA by SAS congruence property
∠1=∠2 and AB=DC By CPCTE
Thus, AB||DC (∠1 and ∠2 are alternate angles equal then lines parallel)
ABCD is a parallelogram. ( If two sides equal and parallel then a parallelogram.
Below is matched table.
DO = OB, AO = OC ⇒ Given
∠ DOC =∠ AOB ⇒ Vertical angles are equal
∆COD ≅ ∆AOB ⇒ SAS CPCTE
∠1 = ∠2, AB = DC ⇒ CPCTE
AB||DC ⇒ If alternate interior angles =, then lines parallel
ABCD is a parallelogram ⇒ If two sides = and ||, then a parallelogram
Please see attachment for figure and matching.
Step-by-step explanation: