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What is the area of a triangle with vertices at (–3, 3), (2, 3), and (4, 7)?

a) 5 square units
b) 10 square units
c) 20 square units
d) 40 square units

Respuesta :

The answer on ED:

B. 10 units


The correct option is Option B: the area of the triangle from the vertices of coordinates (–3, 3), (2, 3), and (4, 7) will be 10 square units.

How to calculate the area of the triangle if the vertices of the triangle are given?

The area of the triangle can be calculated from the coordinate of vertices

Area of the trinagle= Δ= (1/2)|x1(y2−y3) + x2(y3−y1) + x3(y1−y2)|

where (x1,y1), (x2,y2), (x3,y3) are the coordinates of the vertices.

Here given that the coordinates of the vertices of the triangle are (–3, 3), (2, 3), and (4, 7).

So the coordinates x1= -3, y1=3

the coordinates x2=2, y2=3

the coordinates x3=4, y3=7

The area of the triangle can be calculated by using the above formula

Area of the trinagle= Δ= (1/2)|x1(y2−y3) + x2(y3−y1) + x3(y1−y2)|

= (1/2) | (-3)(3-7) + 2(7-3) + 4(3-3)|

= (1/2) | (-3)(-4) + (2*4) +(4*0) |

= (1/2) | 12+ 8+ 0|

= (1/2)|20|

=(1/2)*20

= 10 square units

Therefore the correct option is Option B: the area of the triangle from the vertices of coordinates (–3, 3), (2, 3), and (4, 7) will be 10 square units.

Learn more about the area of the triangle

here: https://brainly.com/question/19044159

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