A small class has
9
students,
5
of whom are girls and
4
of whom are boys. The teacher is going to choose two of the students at random. What is the probability that the first student chosen will be a girl and the second will be a boy? Write your answer as a fraction in simplest form.

[tex]\text{P(first student chosen will be a girl and the second will be a boy)}=\\\text{P(first student chosen will be a girl)}\times \text{P(second student chosen will be a will be a boy)}[/tex]

Working:

[tex]\text{P(first student chosen will be a girl)} = \displaystyle\frac{5}{9}\\\\\text{P(second student chosen will be a boy)} = \displaystyle\frac{4}{8}\\\\[/tex]

[tex]\text{P(first student chosen will be a girl and the second will be a boy)}= \displaystyle\frac{5}{9}\times \frac{4}{8}\\\\\frac{20}{72} = \frac{5}{18}[/tex]

Hence, [tex]\frac{5}{18}[/tex] is the probability that the first student chosen will be a girl and the second will be a boy.

A small class has 9 students, 5 of whom are girls and 4 of whom are boys. The teacher is going to choose two of the students at random. What is the probability that the first student chosen will be a girl and the second will be a boy? Write your answer as a fraction in simplest form.

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A small class has
9
students,
5
of whom are girls and
4
of whom are boys. The teacher is going to choose two of the students at random. What is the probability that the first student chosen will be a girl and the second will be a boy? Write your answer as a fraction in simplest form.