Respuesta :
Hi there
All you have to do is replace a by 2 and b by 7 and solve it.
4(2)^4 - 2(7^2) + 40
4(16)-2(49)+40
64 - 98 + 40
-34 + 40
= 6
Answer : A
Good luck!
All you have to do is replace a by 2 and b by 7 and solve it.
4(2)^4 - 2(7^2) + 40
4(16)-2(49)+40
64 - 98 + 40
-34 + 40
= 6
Answer : A
Good luck!
The value of the expression 4a4 − 2b2 + 40 when a = 2 and b = 7 is 6.
What is PEMDAS rule?
PEM/DA/S is the sequence or order of operations applied to solve an expression.
To remember the operation sequence, we use PEMDAS: Parentheses, Exponents, Multiplication and Division (from left to right), Addition and Subtraction (from left to right).
Given expression:
4a^4 − 2b^2 + 40
At a = 2 and b = 7, expression becomes as:
4(2^4) − 2(7^2) + 40
Using PEMDAS, first solve brackets having exponent terms:
4(16) − 2(49) + 40
Now next solve multiplication part:
64 − 98 + 40
Now solve add and subtract operations:
-34 + 40 = 6
Hence the finale value of the expression 4a4 − 2b2 + 40 when a = 2 and b = 7 is 6.
To learn more about PEMDAS, refer to the link:
https://brainly.com/question/36185
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