There are seven performers who will present their comedy acts this weekend at a comedy club. How many different ways are there to schedule there appearences?

Respuesta :

this is permutations

to arrange n performers in n ways, that is n!

7 in 7 ways is 7! or 7*6*5*4*3*2*1=5040 ways

Seven performers  can be scheduled to perform in that weekend in that comedy club in 5040 different ways.

What is different ways to arrange 'n' number of objects?

In a given set of number, the highest possible arrangements for the numbers in different ways are factorial of the total number in that set.

Let, there are 'n' numbers in the given data set.

Therefore, in order to get the highest possible arrangements of the given set of numbers in different ways we must calculate the n! for the given data set.

Here, the total performers who will present their comedy acts this weekend at a comedy club are 7.

The different ways to schedule their appearances are

[tex]= 7!\\= (7)(6)....(1)\\= 5040[/tex]

Therefore, the seven performers can be scheduled to perform in that weekend in that comedy club in 5040 different ways.

Learn more about different ways to arrange any number of objects here: https://brainly.com/question/13034251?

#SPJ2