so hmmm notice the picture below
if the width is "w", twice that is 2*w or 2w, 7 less than that will then be
2w - 7
thus [tex]\bf \textit{area of a rectangle}\\\\
A=lw\qquad
\begin{cases}
l=length\\
w=width\\
-------\\
A=99\\
l=2w-7
\end{cases}\implies 99=(2w-7)w[/tex]
solve for "w", to see what the width is
what about the length? well, l = 2w - 7
