The area of the floor of a school gymnasium is shown below. The length of the floor is four feet smaller than twice the width, as shown in the diagram below. a) Jonah calculated the area of the gym to be w^2 +2w -4. Is jonahs calculation right? b)The school decided to add bleaches to the gym floor. The school expanded the floor by adding 12 feet to the width and 15 feet to the length. Write the polynomial expression in simplified form that represents the total gym floor 3)The school decided to build a new gym to the old one. The total area of the new gym floor is represented by the new expression 2w^2 +19w +35. Determine the new length and width of the new gym floor in terms of w. Show work. Explain why you did each step.

Respuesta :

A.) Let, The width = w
Then, Length = 2w - 4

Area = Length * Width
A = w(2w - 4)
A = 2w² - 4w

So, Jonahs calculation was Wrong.

B.) New Width = (w + 12)
New Length = (2w - 4 + 15) = (2w + 11)

Area = (w + 12) (2w + 11)
A = 2w² + 35w + 132

C.) 2w² + 19w + 35
= 2w² + 14w + 5w + 35
= 2w(w + 7) 5(w + 7)
= (2w + 5) (w+ 7)

Hope this helps!
= (2w + 5) (w+ 7) he is right!