Respuesta :
To factor all you do is...
Factor 2x3+14x2+6x+422x3+14x2+6x+42=2(x+7)(x2+3)Answer:2(x+7)(x2+3)
Factor 2x3+14x2+6x+422x3+14x2+6x+42=2(x+7)(x2+3)Answer:2(x+7)(x2+3)
Answer:
[tex]2\cdot{(x+1)\cdot{(x^2+3)}[/tex]
Step-by-step explanation:
We can take out 2 to as this is common in each term:
[tex]2\cdot{x^3}+14\cdot{x^2}+6\cdot{x}+42[/tex]
[tex]2\cdot{(x^3+7\cdot{x^2}+3\cdot{x}+21)}[/tex]
We can see that the use factors of 21 which are 1, 3, 7 and 21 (all ± values). We can use -7 and the coefficients of the simplified expression to determine if one of the values is zero when -7 is multiplied and added to the coefficients:
-7] 1 7 3 21
Bring down 1
-7] 1 7 3 21
____-7_ 0_-21____
1 0 3 0
We can see that the factor of -7 yields two zeros, but the final answer is zero and therefore we can use 7 factor and the answers it yielded:
We can simplify the expression using 1, 0 and 3.
[tex]2\cdot{(x+7)\cdot{(x^2+0\cdot{x}+3)}[/tex]
[tex]2\cdot{(x+7)\cdot{(x^2+3)}[/tex]
