Suppose that the spinner is spun twice. Find the probabilities:
[tex]Pr(X=0),\ Pr(X=1),\ Pr(X=2).[/tex]
1. When X=0, blue occurs 0 times. There is one favorable outcome (RR) from four possible. Then
[tex]Pr(X=0)=\dfrac{1}{4}.[/tex]
2. When X=1, blue occurs 1 times. There are two favorable outcomes (RB and BR) from four possible. Then
[tex]Pr(X=1)=\dfrac{2}{4}=\dfrac{1}{2}.[/tex]
3. When X=2, blue occurs 2 times. There is one favorable outcome (BB) from four possible. Then
[tex]Pr(X=2)=\dfrac{1}{4}.[/tex]
At last, the distribution table takes look
[tex]\begin{array}{cccc}x_i &|\ 0 & 1 & 2 \\------& -- &---&--- \\Pr(X=x_i) & \left |\ \dfrac{1}{4} & \dfrac{1}{2} & \dfrac{1}{4}\end{array}[/tex]
