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In the balanced redox reaction 2 al(s) 6 hcl(aq) → 2 alcl3(aq) 3 h2(
g. 80.0 ml of 2.0 m hcl would (theoretically) react with how many grams of al(s)? assume that the reaction is quantitative.
a. 1.44 g
b. 4.32 g
c. 1,440 g
d. 2,030 g
e. none of the above

Respuesta :

Saimon4520
2 moles of AL will react with 6 moles of HCl.

2M HCl = 2 mol / dm^3

80ml = 0.08L = 0.08dm^3

In 0.08 dm^3, there are 0.16 moles of HCl.

So 0.053 moles of Al will react with 0.16 moles of HCl.

0.053 * 27 (mass of Al) = 1.44g

answer is 1.44 grams of Al (s) needed.

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