The quadratic equation is ax^2 + bx + c = 0, where a, b, and c are constants.
In the given expression, 2x^2 - 5a + 6 = 0, so a = 2, b = -5, and c = 6.
The quadratic formula is x = [-b ± √(b^2 - 4ac)] / 2a
Substituting the values, we get:
x = [-(-5) ± √((-5)^2 - 4(2)(6))] / 2(2)
x = [5 ± √(25 - 48)] / 4
x = [5 ± √(-23)] / 4
As the square root of a negative number is not a real number, the solution is in radical form. Therefore, the solution is:
x = (5 ± √23 i) / 4, where i is the imaginary unit.
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