One side of a triangle is half the longest side. The third side is 8 m less than the longest side
Let x,x/2 and (x-8m) represent these sides
x + x/2 + (x-8m) = 42m
Solving for x
5/2x = 50m
x = 20m, the longest side. The other two are 10m and 12m
Three sides are: 10m,12m and 20m