Respuesta :

-log (1.2x10^-2) = 1.92 so C

Answer: The pH of the solution is 1.92

Explanation:

To calculate the pH of the solution, we use the equation:

[tex]pH=-\log[H^+][/tex]

We are given:

Hydrochloric acid is a monoprotic acid and it dissociates 1 mole of hydrogen ions. So, the concentration of hydrogen ions is [tex]1.20\times 10^{-2}M[/tex]

[tex][H^+]=1.20\times 10^{-2}M[/tex]

Putting values in above equation, we get:

[tex]pH=-\log(1.20\times 10^{-2})\\\\pH=1.92[/tex]

Hence, the pH of the solution is 1.92