If 40 kJ of heat energy are added to 4 kg of water at 30°C, what will be the final temperature of the water? The specific heat of water is 4186 J/(kg·°C)

Respuesta :

Heat gained or added in a system can be calculated by multiplying the given mass to the specific heat capacity of the substance and the temperature difference. It is expressed as follows:

Heat = mC(T2-T1)
40000 = 4(4186)(T2 - 30.0)
T2 = 32.4 degrees Celsius