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MissPhiladelphia
Assuming that this gas is in ideal state, we can use the relation that for every 1 mol of an ideal gas it would have a volume of 22.4 L. But before using this, relation we need to convert the number of grams of H2 into moles by using the molar mass of 2.02 g/mol.

moles H2 = 0.00922 g ( 1 mol / 2.02 g ) = 0.005 mol H2

Volume H2 at STP = 0.005 mol H2 ( 22.4 L / 1 mol ) = 0.102 L of H2
okpalawalter8

We have that the Volume of H2  is mathematically given as

V=0.102L of H2

Volume

Question Parameters:
What volume in milliliters will 0.00922 g of h2 gas occupy at stp

Generally the equation for the Volume  is mathematically given as

[tex]V=\frac{nRT}{P}[/tex]

Where

moles of h2=1/2.o2 *0.00922

moles of h2=0.005h2

Therefoe

[tex]V=\frac{0.005*22.4}{1}[/tex]

V=0.102L of H2

For more information on Volume  visit

https://brainly.com/question/1578538

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