Note that this force does [tex]20 \, N \cdot 5.2 \, m = 104 \, J[/tex] of work. Then, by conservation of energy, we have that:
[tex]\frac{mv^2}{2} = 104 \, J[/tex]
Substituting [tex]m=22 \, kg[/tex], we see that:
[tex]11v^2 \, kg = 104 \, J[/tex]
Then, dividing by [tex]11[/tex] and taking the square root, we see that:
[tex]v=~3.1 \, m/s[/tex]
