Respuesta :
[tex]i^{233}=i^{232+1}=i^{232}i[/tex]
Since 232 is divisible by 4, and [tex]\dfrac{232}4=58[/tex], you have
[tex]i^{232}i=\left(i^4\right)^{58}i=1^{58}i=i[/tex]
Since 232 is divisible by 4, and [tex]\dfrac{232}4=58[/tex], you have
[tex]i^{232}i=\left(i^4\right)^{58}i=1^{58}i=i[/tex]