suppose a sample of bone fossil contains 5.2% of the carbon-14 found in an equal amount of carbon in present-day bone. estimate the age of the fossil, assuming an exponential decay model. the half-life of carbon-14 is approximately 5700 years.

Respuesta :

The age of the fossil is 24, 312 years assuming an exponential decay model.

Exponential decay model refers to model in which the amount of something decreases at a rate proportional to the amount left and this rate is given by a constant ratio k. The formula for remaining quantities of a substance is given by:

P = 100 e^(-kt)

Where P is the remaining quantity, k is the constant of decay, and t is time.

As the half life of the carbon 14 is 5700, when 50% of the substance remains,

50 = 100 e^(-5700k)

1/2 = e^(-5700k)

In(1/2) = In(e^(-5700k))

- In (2) = -5700k

k = In(2)/5700 = 0.0001216

Since, 5.2% carbon-14 remains,

5.2 = 100 e^(-0.0001216t)

0.052 = e^(-0.0001216t)

In(0.0052) = - 0.0001216

t = In(0.052) * - 0.0001216

t ≈ 24, 312 years.

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