Ride's rotation that will keep the student pinned to the wall once the floor drops is 3.97 sec.
rotation is a type of trasfermation that takes each point in a figure and rotates its a certain number.
Mass of student = 50 kg
Coefficient of static friction \mu = 0.8 μ=0.8
Ride diameter d = 10 m d=10m
Ride radius r = \frac{d}{2} = 5 m r= 2d
=5m
Acceleration due to gravity g = 10 m/s^2 g=10m/s
2
Maximum period of ride's rotation =
Formula: \text{ Maximum period } = \500{\text{ Circumference }}{\10m/s{ Velocity }} Maximum period =
Velocity
Circumference
Step 1: Calculating the static frictional force and normal force
This frictional force will be equal to the student's weight to
find out what minimum static frictional force is required
Hence, maximum period of ride's rotation P = 3.97 P=3.97 sec
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