Respuesta :

The density of a gas with a molar mass of 28.011gmol at 281 k and 1.90 atm is 2.30 g/l or grams per liter.

The formula for the ideal gas constant is PV= nRT

[tex]\frac{P}{RT}= \frac{n}{V}[/tex] = molarity

[tex]\frac{n}{V}[/tex] = molarity

Using M = molar mass to multiply both sides, we obtain

[tex]\frac{PM}{RT} = \frac{nM}{V}[/tex]

We can write [tex]\frac{PM}{RT}[/tex]= ρ.......equation (i)

since density, ρ = [tex]\frac{mass}{volume}[/tex] and

density, ρ= [tex]molarity*molar mass (\frac{nM}{V})[/tex]

After plugging in all the numbers in equation (i), we get

ρ= [tex]\frac{ 1.90*28.011}{281*0.082}[/tex]

ρ= [tex]\frac{522090}{2304200}[/tex]

ρ= 2.30 g/l.

To learn more about molar mass, refer:-

https://brainly.com/question/22997914

#SPJ4