in an embryo with a complete deficiency of pyruvate kinase, how many net moles of atp are generated in the conversion of 1 mole of glucose to 1 mole of pyruvate?

Respuesta :

In embryos with a complete deficiency of pyruvate kinase, the net moles of ATP converted from 1 mole of glucose to 1 mole of pyruvate is 0.

Pyruvate kinase is an enzyme involved in the last step of glycolysis that catalyzes the transfer of a phosphate group from phosphoenolpyruvate (PEP) to adenosine diphosphate (ADP), yielding one molecule of pyruvate and one molecule of ATP.

The 2 molecules formed are used for several chemical reactions that are endergonic. Thus, the total ATP produced in this reaction is 2 ATP.

Net ATP = 2 ATP produced - needed 2 ATP = net 0 ATP produced.

Thus the net ATP production will be zero. It is unlikely that the embryo will survive with a complete lack of this enzyme.

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