a 3000 kg truck travelling at 50 km/hr strikes a stationary 1000 kg car, locking the two vehicles together. a) what is the final velocity of the two vehicles?) b) how much of the initial kinetic energy is lost to the

Respuesta :

The final velocity of the two vehicles is 37.5 kph and the initial kinetic energy lost is 0.25Joule

a) Prior to and following the impact, momentum is preserved as follows:

3000×50 = 4000×X

X = 37.5 kph

afterward, 37.5km/h is 10.4166m/s so it’s 4000*10.4166²/2 or about 217000 Joule

so 73000 Joule were lost in the collision

b) The portion lost is calculated as the difference between the kinetic energy before and after the collision, divided by the initial energy:

(1/2×3000×50² - 1/2×4000×37.5²) / (1/2 × 3000 × 50²) = 0.25 Joule

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