contestada

a company produces steel rods. the lengths of the steel rods are normally distributed with a mean of 155.1-cm and a standard deviation of 1.4-cm. for shipment, 30 steel rods are bundled together. find the probability that the average length of a randomly selected bundle of steel rods is greater than 155.8-cm. p(m > 155.8-cm)

Respuesta :

The probability that the average length of a randomly selected bundle of steel rods is 155.8 then P = 0.174 cm

Given sample size 'n' = 30 steel rods

Mean of the Population = 155.1 cm

Standard deviation of the Population = 1.4 cm

Given x⁻ be the random variable of Normal distribution

Let x₁⁻ =  155.8cm

The probability that the average length of a randomly selected bundle of steel rods is  155.8-cm.

P(x⁻₁ < x⁻ <x⁻₂) = P(Z₁ < Z <Z₂)

                      = P(Z <Z₂) - P(Z<Z₁)

                     = 0.5 +A(1.629) - (0.5 +A(0.7541)

                     = A(1.629) - A(0.7541)

                     = 0.4474 - 0.2734

                     = 0.1

The probability that the average length of a randomly selected bundle of steel rods is 155.8 cm = 0.174

learn more about of probability here

https://brainly.com/question/16752717

#SPJ4

Otras preguntas