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a mass m is attached to a spring with a spring constant k. if the mass is set into motion by a displacement d from its equilibrium position, what would be the speed, v, of the mass when it returns to equilibrium position?

Respuesta :

Answer: The mass when it returns to equilibrium position V=d√(k/m)

Reason:

The mass of the spring is set into simple harmonic motion at the equilibrium position A mass attached to a spring is free to oscillate, with angular velocity ω, in a horizontal plane without friction or damping. It is pulled to a distance X0 and pushed towards the centre with a velocity V0 at time t = 0.

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