Given
The probability distribution for the random variable X is,
X - 6 7 8 9 10
P(X) - 0.31 0.23 0.11 0.26 0.09
To find the probability of the random variable X being at least seven.
Explanation:
It is given that,
The probability distribution for the random variable X is,
X - 6 7 8 9 10
P(X) - 0.31 0.23 0.11 0.26 0.09
Then,
[tex]\begin{gathered} P(at\text{ }least\text{ }7)=P(X=7)+P(X=8)+P(X=9)+P(X=10) \\ =1-P(6) \\ =1-0.31 \\ =0.69 \end{gathered}[/tex]
Hence, the probability of the random variable X being at least seven is 0.69.
