In order to solve this exercise, you need to use the following property of Radicals:
[tex]\sqrt[n]{b^n}=b^{\frac{n}{n}}=b^1=b[/tex]Given:
[tex]\sqrt[]{48}[/tex]The first step is to descompose the Radicand (in this case it is 48) into its prime factors:
[tex]48=2\cdot2\cdot2\cdot2\cdot3=2^4\cdot3[/tex]Rewrite the Radicand:
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