We have the following equation:
[tex]f(x)=108208e^{0.3387x}[/tex]where x denotes the number of years after 1998.
By substituting the given information, we have that
[tex]7.4=1.8208e^{0.3387x}[/tex]and we need to find x. Then, by dividing both sides by 1.8208, we get
[tex]e^{0.3387x=}4.0641475[/tex]then by taking natural logarithm to both sides, we obtain
[tex]0.3387x=ln(4.0641476)[/tex]which gives
[tex]0.3387x=1.4022040[/tex]then, the number of years after 1998 is:
[tex]\begin{gathered} x=\frac{1.4022040}{0.3387} \\ x=4.13996 \end{gathered}[/tex]which means 4 years after 1998. Then, by rounding to the nearest year, the answer is 2002.