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Given a material of specific heat c in Cal/gramC^o and mass 6 grams. If the material is heated by absorbing 7 calories of heat then which of these expressions yields the change in temperature of the material in Celsius degrees? A)7 divided by (c - 6) B)7 times (c - 6) C)7 divided by (6 times c)

Respuesta :

Given:

The mass is m = 6 grams.

The heat absorbed is Q = 7 calories.

The unit of specific heat, c of the material is cal/gram degree Celsius

To find the change in temperature of the material in degrees Celsius.

Explanation:

The formula to calculate the temperature change is

[tex]\begin{gathered} Q\text{ = mc}\Delta T \\ \Delta T=\frac{Q}{mc} \end{gathered}[/tex]

Substituting the values, the change in temperature will be

[tex]\Delta T\text{ = }\frac{7}{6\times c}[/tex]

Final Answer: The change in temperature will be 7 divided by (6 times c).

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