Okay, here we have this:
Considering the provided information, we are going to calculate the volume of the cone, so we obtain the following:
We will substitute in the following formula for the volume of a cone:
[tex]V=\frac{1}{3}\pi R^2h[/tex]Replacing we obtain:
[tex]\begin{gathered} V=\frac{1}{3}\pi(11yd)^2\cdot(15yd) \\ V=\frac{1}{3}\pi121yd^2\cdot15yd \\ V=5yd\cdot121yd^2\cdot\pi \\ V=605\pi yd^3 \\ V=605(3.14)yd^3 \\ V=1899.7yd^3 \end{gathered}[/tex]Finally we obtain that the volume of the cone is approximately 1899.7yd^3.
